【已解决】IDE中支持XMLHttpRequest吗？向其它服务器请求数据status返回0

始终无法获取数据，代码如下：

var xmlObj = new XMLHttpRequest();

function createXMLHttpRequest(){

    if(window.ActiveXObject){

        try{

            xmlobj = new ActiveXObject("Msxml2.XMLHTTP");

        }catch(e){

            try{

                xmlobj = new ActiveXObject("Microsoft.XMLHTTP");

            }catch(E){

                xmlobj = false;

            }

        }

    }else if(window.XMLHttpRequest){

        xmlobj = new XMLHttpRequest();

    }

}



function myPost(cityName){

    createXMLHttpRequest();

    //var _host ='ws.webxml.com.cn';

    //var _post = '/WebServices/WeatherWS.asmx/getWeather';

    //var url = _host + _post;

    //var url = 'ws.webxml.com.cn/WebServices/WeatherWS.asmx/getWeather';

    var url = 'ws.webxml.com.cn/WebServices/WeatherWS.asmx/getWeather?theCityCode=北京&theUserID=';

    //var pram = 'theCityCode='+cityName;

    xmlObj.onreadystatechange = onResponse;

    xmlObj.open("GET",url,true);

    //xmlObj.setRequestHeader('Content-Type','text/xml');

    //xmlObj.setRequestHeader('Content-Type','application/x-www-form-urlencoded');

    //xmlObj.setRequestHeader('Content-Length',pram.length);

    xmlObj.send(null);

}



function onResponse()

{

    var scene = mugeda.scene;

    var txt = scene.getObjectByName('txt');

    txt.text = ' ['+xmlObj.status+'] ::';

    txt.text += xmlObj.responseXML;

}



mugeda.addEventListener('renderReady',function(){

    myPost('');



});